You must log in or register to comment.
It’s the same in the the standard c library, so Java is being consistent with a real programming language…
Doubles have a much higher max value than ints, so if the method were to convert all doubles to ints they would not work for double values above 2^31-1.
(It would work, but any value over 2^31-1 passed to such a function would get clamped to 2^31-1)
So why not return a long or whatever the 64 bit int equivalent is?
To avoid a type conversion that might not be expected. Integer math in Java differs from floating point math.
Math.floor(10.6) / Math.floor(4.6) = 2.5 (double)
If floor returned a long, then
Math.floor(10.6) / Math.floor(4.6) = 2 (long)
If your entire code section is working with doubles, you might not like finding Math.floor() unexpectedly creating a condition for integer division and messing up your calculation. (Have fun debugging this if you’re not actively aware of this behavior).
But there’s really no point in flooring a double outside of the range where integers can be represented accurately, is there.
Logic, in math, if you have a real and you round it, it’s always a real not an integer. If we follow your mind with abs(-1) of an integer it should return a unsigned and that makes no sense.
in math, if you have a real and you round it, it’s always a real not an integer.
No, that’s made up. Outside of very specific niche contexts the concept of a number having a single well-defined type isn’t relevant in math like it is in programming. The number 1 is almost always considered both an integer and a real number.
If we follow your mind with abs(-1) of an integer it should return a unsigned and that makes no sense.
How does that not make sense? abs is always a nonnegative integer value, why couldn’t it be an unsigned int?
Makes sense, how would you represent
floor(1e42) orceil(1e120)as integer? It would not fit into 32bit (unsigned) or 31bit (signed) integer. Not even into 64bit integer.BigInt (yeah, not native everywhere)
I feel this is worse than double though because it’s a library type rather than a basic type but I guess ceil and floor are also library functions unlike toInt
